GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The logo of a certain corporations is in the shape of a poly
[#permalink]
17 Feb 2018, 08:13
17 Feb 2018, 08:13
2
00:00
Question Stats:
64% (01:38) correct
35% (03:14) wrong based on 14 sessions
Hide Show timer Statistics
The logo of a certain corporation is in the shape of a polygon, where all angles of the polygon have equal measures. In the figure, V is one vertex of the polygon. If Y, in degrees is the measure of an angle of the polygon and y = 5x, how many sides does the polygon have?
A)5
B)6
C)10
D)12
E)30
A)5
B)6
C)10
D)12
E)30
Attachments
polygon.png [ 6.08 KiB | Viewed 2590 times ]
Re: The logo of a certain corporations is in the shape of a poly
[#permalink]
20 Feb 2018, 01:53
20 Feb 2018, 01:53
2
an angle of a regular polygon is given by a formula \(\frac{(n-2)*180}{n}\)
Hence we have y = \(\frac{(n-2)*180}{n}\)
here, \(n\) = no of sides of the polygon
\(X\) here is an external angle of the polygon
external angles of a regular polygon add up to 360 degrees
therefore \(x = 360/n\)
Given that,
\(y = 5X\)
\(5X =\) \(\frac{(n-2)*180}{n}\)
\(5X*n = (n-2)*180\)
\(5* 360 = (n-2)*180\)
solve for n; \(n = 12\)
option D
Hence we have y = \(\frac{(n-2)*180}{n}\)
here, \(n\) = no of sides of the polygon
\(X\) here is an external angle of the polygon
external angles of a regular polygon add up to 360 degrees
therefore \(x = 360/n\)
Given that,
\(y = 5X\)
\(5X =\) \(\frac{(n-2)*180}{n}\)
\(5X*n = (n-2)*180\)
\(5* 360 = (n-2)*180\)
solve for n; \(n = 12\)
option D
Re: The logo of a certain corporations is in the shape of a poly
[#permalink]
22 Feb 2018, 13:13
22 Feb 2018, 13:13
Nice solution!
amorphous wrote:
an angle of a regular polygon is given by a formula \(\frac{(n-2)*180}{n}\)
Hence we have y = \(\frac{(n-2)*180}{n}\)
here, \(n\) = no of sides of the polygon
\(X\) here is an external angle of the polygon
external angles of a regular polygon add up to 360 degrees
therefore \(x = 360/n\)
Given that,
\(y = 5X\)
\(5X =\) \(\frac{(n-2)*180}{n}\)
\(5X*n = (n-2)*180\)
\(5* 360 = (n-2)*180\)
solve for n; \(n = 12\)
option D
Hence we have y = \(\frac{(n-2)*180}{n}\)
here, \(n\) = no of sides of the polygon
\(X\) here is an external angle of the polygon
external angles of a regular polygon add up to 360 degrees
therefore \(x = 360/n\)
Given that,
\(y = 5X\)
\(5X =\) \(\frac{(n-2)*180}{n}\)
\(5X*n = (n-2)*180\)
\(5* 360 = (n-2)*180\)
solve for n; \(n = 12\)
option D
