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Re: (a+1)(b+1) [#permalink]
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It's pretty simple:

First let's simplify the value of Quantity A: (a + 1)(b + 1) = ab + a + b + 1

As we don't know whether (a + b) is positive, negative or 0.

So Choice D is correct.
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Re: (a+1)(b+1) [#permalink]
A: (a+1)(b+1) = ab + a + b + 1
B : ab + 1

ab + a + b + 1 ? ab + 1
a + b ? 0
if a and b are negative or totally when a+b <0 A is less.
if a = -b, A and B are equal.
if a+b > 0, B is less.
So we can't recognize which one is less or more and D is correct.
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Re: (a+1)(b+1) [#permalink]
I think if you enter the exam and mark all QC "D", there is a huge probability that you gotta have 50% more percent right :D
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Re: (a+1)(b+1) [#permalink]
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