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Re: What is the value of when z = 3x, y = 4z, and xy ≠ 0 ? 12 1
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18 Mar 2018, 06:45
Explanation
You know that \(\frac{xy}{z^2}\), so solve this one by plugging in values for z, x, and y. If x = 12, then z = 36 and y = 144; \(\frac{xy}{z^2}=\frac{12\times 144}{36^2}=\frac{4}{3}\). The correct answer is choice (B).