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For all real numbers, let a^* = 1 - a
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18 Mar 2018, 10:45
18 Mar 2018, 10:45
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Question Stats:
82% (00:32) correct
17% (00:44) wrong based on 229 sessions
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For all real numbers, let \(a^* = 1 - a\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(((-1)^*)^*\) |
\(2^*\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: For all real numbers, let a^* = 1 - a
[#permalink]
19 Mar 2018, 16:24
19 Mar 2018, 16:24
1
Answer: C
a* = 1 - a
(-1)* = 1 - (-1) = 2 so ((-1)*)* = 2*
So A and B are equal. And answer is C.
a* = 1 - a
(-1)* = 1 - (-1) = 2 so ((-1)*)* = 2*
So A and B are equal. And answer is C.
Re: For all real numbers, let a^* = 1 - a
[#permalink]
20 Mar 2018, 00:31
20 Mar 2018, 00:31
Need some help here. I solved it this way:
A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2
So, B > A.
is this right?
A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2
So, B > A.
is this right?
