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If 42.42 = k(14 + m/50), where k and m are positive integers
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25 Mar 2018, 10:43
25 Mar 2018, 10:43
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Question Stats:
67% (01:36) correct
32% (02:23) wrong based on 49 sessions
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If \(42.42 = k(14 + \frac{m}{50})\), where \(k\) and \(m\) are positive integers and \(m < 50\), then what is the value of \(k + m\) ?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
Re: If 42.42 = k(14 + m/50), where k and m are positive integers
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25 Mar 2018, 19:18
25 Mar 2018, 19:18
1
Great question!
Start out by simplifying the equation you get
42.42*50 = (14*50 +m)*k
2121 = (700 +m)*k
Factors of 2121 = 3*7*101 => 707*3
so (700+m)*k can be write (700+7)*3
so m = 7 and k = 3 hence m+k = 10
Start out by simplifying the equation you get
42.42*50 = (14*50 +m)*k
2121 = (700 +m)*k
Factors of 2121 = 3*7*101 => 707*3
so (700+m)*k can be write (700+7)*3
so m = 7 and k = 3 hence m+k = 10
Re: If 42.42 = k(14 + m/50), where k and m are positive integers
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28 May 2018, 22:10
28 May 2018, 22:10
3
42.42 = 42 + 0.42
=42 42/100 as mixed fraction or 42 21/50
3*14 = 42.
Hence k =3.
3*m = 21.
Hence m =7
On addind both we get 10.
=42 42/100 as mixed fraction or 42 21/50
3*14 = 42.
Hence k =3.
3*m = 21.
Hence m =7
On addind both we get 10.
