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When m is divided by 5 the remainder is 2
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03 Apr 2018, 18:41
03 Apr 2018, 18:41
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78% (01:00) correct
21% (01:11) wrong based on 70 sessions
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When m is divided by 5 the remainder is 2
When n is divided by 5 the remainder is 1
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
When n is divided by 5 the remainder is 1
Quantity A |
Quantity B |
The remainder when m + n is divided by 5 |
The remainder when mn is divided by 5 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: When m is divided by 5 the remainder is 2
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07 Apr 2018, 21:19
07 Apr 2018, 21:19
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Possible values of \(M = 2, 7, 12, 17\),.....
Possible values of \(N = 1, 6, 11, 16\),.....
Possible value of \(M + N = 3, 13, 23, 33,....\),
Possible value of \(M*N = 2, 42, 132, 272,....\)
All of the values \(3, 13, 23, 33\) and so on when divided by\(5\) gives a remainder of 3
All of the values \(2, 42, 132, 272\) and so on gives a remainder of 2 when divided by 5
option A
Possible values of \(N = 1, 6, 11, 16\),.....
Possible value of \(M + N = 3, 13, 23, 33,....\),
Possible value of \(M*N = 2, 42, 132, 272,....\)
All of the values \(3, 13, 23, 33\) and so on when divided by\(5\) gives a remainder of 3
All of the values \(2, 42, 132, 272\) and so on gives a remainder of 2 when divided by 5
option A
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Re: When m is divided by 5 the remainder is 2
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09 Apr 2018, 19:06
09 Apr 2018, 19:06
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Expert Reply
On a remainder question like this, the easiest way to solve the problem is simply to make a column of numbers that the variable could be. What's the smallest number that m could be? Many would say 7, but actually the smallest number that it could be is the remainder itself: 2. After all, if 2 is divided by 5, you get 0, remainder 2. Let's make some columns showing the first 5 possible values for m and n:
m -- n
2 -- 1
7 -- 6
12 - 11
17 - 16
22 - 21
Notice they increase by 5 each time. Now, for quantity A, if we add any number in the m column with any number in the n column and divide by 5, we'll always get a remainder of 3.
For quantity B, if we multiply any number from column m with any number in column n, and divide by 5, we'll always get a remainder of 2. Thus the answer is A.
m -- n
2 -- 1
7 -- 6
12 - 11
17 - 16
22 - 21
Notice they increase by 5 each time. Now, for quantity A, if we add any number in the m column with any number in the n column and divide by 5, we'll always get a remainder of 3.
For quantity B, if we multiply any number from column m with any number in column n, and divide by 5, we'll always get a remainder of 2. Thus the answer is A.
