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If (2x/3 - 3)^3=0
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07 Apr 2018, 02:22
07 Apr 2018, 02:22
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Question Stats:
83% (00:56) correct
16% (01:29) wrong based on 18 sessions
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If \((\frac{2x}{3} - 3)^3=0\), then x=
A. \(\frac{2}{9}\)
B. \(\frac{8}{27}\)
C. \(\frac{2}{3}\)
D. \(\frac{3}{2}\)
E. \(\frac{9}{2}\)
A. \(\frac{2}{9}\)
B. \(\frac{8}{27}\)
C. \(\frac{2}{3}\)
D. \(\frac{3}{2}\)
E. \(\frac{9}{2}\)
Re: If (2x/3 - 3)^3=0
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07 Apr 2018, 23:49
07 Apr 2018, 23:49
1
for the equation in question =0, the term in the parenthesis should be zero.
2x/3 - 3 = 0
2x/3 = 3
2x = 9
x = 9/2
Hence E
for cube of a number to be zero, the number itself should be zero.
2x/3 - 3 = 0
2x/3 = 3
2x = 9
x = 9/2
Hence E
for cube of a number to be zero, the number itself should be zero.
Re: If (2x/3 - 3)^3=0
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27 Jul 2022, 23:15
27 Jul 2022, 23:15
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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