novice07 wrote:
If P(A) = 0.8 and P(B) = 0.7, then Events A and B have to be independent for P(A and B) to be 0. Since they are not (which we assume when not given otherwise) there must be some intersection of these events.
So, if P(A) is 0.8 and P(B) is 0.7 then P(A and B)maximum would be 1, since it can't exceed 1.
Your concept is weak. For independent events, events are said not to affect each other, but they can both occur.
For example, the tail of a coin can occur with a dice rolling 6.
however, mutually exclusively events would not allow both events to occur, for example the tail and the face of a coin can not both occur.
Also the it is the maximum of (A or B) NOT (A and B) is 1. you should draw 2 circles which one stands for P(A) 0.8, the other stands for P(B) 0.7. Then the maximum of (A and B) is 0.7 when P(B) 0.7 is included in P(A) 0.8.
That maximum of P(A or B) NOT (A and B) was an overlook. Sorry for that.
I know that independent events can occur together and in that case P(A and B) would be P(A)*P(B). Appreciate for the example. However, I just meant that P(A or B) can't be equal to 1.5 because if two events having probabilities 0.7 and 0.8, it is not possible to have zero intersection.
10 Apr 2018, 01:37 
