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For all integers a nd b, where a is different from b
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11 Apr 2018, 08:22
11 Apr 2018, 08:22
Expert Reply
00:00
Question Stats:
94% (00:31) correct
5% (00:41) wrong based on 38 sessions
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For all integers and b, where a is \(a \neq b\), \(a \ast b = |\frac{(a^2 - b^2)}{(a - b)}|\). What is the value of \(4 \ast 2\)?
A. 2
B. 4
C. 6
D. 8
E. 10
A. 2
B. 4
C. 6
D. 8
E. 10
Re: For all integers a nd b, where a is different from b
[#permalink]
11 Apr 2018, 09:09
11 Apr 2018, 09:09
There is a typo in the question.
(a+b)(a-b)/(a-) = a+b
(a+b)(a-b)=a^2+b^2
4*2 = 4+2
Hence C
(a+b)(a-b)/(a-) = a+b
(a+b)(a-b)=a^2+b^2
4*2 = 4+2
Hence C
Re: For all integers a nd b, where a is different from b
[#permalink]
11 Apr 2018, 13:15
11 Apr 2018, 13:15
Expert Reply
Where is the typo ??
Please point out so I can fix it. If any
Please point out so I can fix it. If any
