Given that \(ab\) is a two digit number \(a\) cannot be \(0\) since \(0b = b\)

so probable values for \(a =1,2,3,4,5,6\)
\(a\) cannot also be more than \(6\) since a is an integer and adding \(3\) to \(7\) or more will make b a two digit number in itself which is not possible
for every given value of \(a\) in the list in order, \(b = 4,5,6,7,8,9\)

so \(ab = 14,25,36,47,58,69\)
hence, \(ba = 41,52,63,74,85,96\)

comparing \(ab\) to \(ba\) according to the respective \(1st-6th\) term above
B>A