Last visit was: 07 Apr 2025, 13:27 It is currently 07 Apr 2025, 13:27
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

a ≠ –b

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
sandy
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11360 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
a ≠ –b [#permalink] New post   15 Apr 2018, 04:34
Expert Reply
00:00

Question Stats:

79% (00:46) correct 20% (01:14) wrong based on 44 sessions

Hide Show timer Statistics

a ≠ –b

Quantity A
Quantity B
\(\frac{6a^2+12ab+6b^2}{(a+b)}\)
\(6(a+b)\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 1
Question: 5
Page: 511
ShowHide Answer
Official Answer
C
User avatar
sandy
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11360 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Re: a ≠ –b [#permalink] New post   18 Apr 2018, 15:44
Expert Reply
Explanation

Whenever you see exponents, think common quadratics.

If you factor the 6 out of the numerator in Quantity A, you get \(6(a^2 + 2ab + b^2)\), which includes a common quadratic \((a +b)^2\).

Then you can cancel (a + b) from both the numerator and the denominator; Quantity A is really just 6(a + b). The quantities are equal.
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12348 [2]
Given Kudos: 136
Send PM

Top Member of the Month
Re: a ≠ –b [#permalink] New post   06 Sep 2021, 10:16
2
sandy wrote:
a ≠ –b

Quantity A
Quantity B
\(\frac{6a^2+12ab+6b^2}{(a+b)}\)
\(6(a+b)\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 1
Question: 5
Page: 511


Given:
QUANTITY A: \(\frac{6a^2+12ab+6b^2}{(a+b)}\)

QUANTITY B: \(6(a+b)\)


First factor out the 6 from numerator in Quantity A to get:
QUANTITY A: \(\frac{6(a^2+2ab+b^2)}{(a+b)}\)

QUANTITY B: \(6(a+b)\)


Now factor quadratic in Quantity A to get:
QUANTITY A: \(\frac{6(a+b)(a+b)}{(a+b)}\)

QUANTITY B: \(6(a+b)\)


The \((a+b)\) terms cancel out in the denominator and numerator in Quantity A to get:
QUANTITY A: \(6(a+b)\)
QUANTITY B: \(6(a+b)\)

Answer: C
User avatar
bumpbot
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5232
Own Kudos [?]: 77 [0]
Given Kudos: 0
Send PM
Re: a b [#permalink] New post   22 Jan 2024, 13:56
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
gmatclubot
Re: a b [#permalink]
22 Jan 2024, 13:56
Moderators:
adewale223
GRE Instructor
108 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1131 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact