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x2 – 2xy + y2 = 0 and y =
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15 Apr 2018, 04:45
15 Apr 2018, 04:45
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Question Stats:
68% (01:18) correct
31% (01:22) wrong based on 47 sessions
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\(x^2 - 2xy + y^2 = 0\) and \(y =\frac{9}{x}\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(y\) |
\(3\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 10
Page: 512
Question: 10
Page: 512
Re: x2 – 2xy + y2 = 0 and y =
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22 Apr 2018, 12:25
22 Apr 2018, 12:25
2
Expert Reply
Explanation
Factor the quadratic expression to get \((x - y)(x - y) = 0\); \(x - y\) must equal 0, so you know that x = y.
Thus, \(y=\frac{9}{y}\) , \(y^2 = 9\), and \(y = 3\) — eliminate choices (A) and (B)—or –3—eliminate choice (C). The answer is choice (D).
Factor the quadratic expression to get \((x - y)(x - y) = 0\); \(x - y\) must equal 0, so you know that x = y.
Thus, \(y=\frac{9}{y}\) , \(y^2 = 9\), and \(y = 3\) — eliminate choices (A) and (B)—or –3—eliminate choice (C). The answer is choice (D).
Re: x2 2xy + y2 = 0 and y =
[#permalink]
20 Apr 2024, 09:35
20 Apr 2024, 09:35
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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