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ab^2
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16 Apr 2018, 15:11
16 Apr 2018, 15:11
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Question Stats:
97% (00:30) correct
2% (00:55) wrong based on 157 sessions
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Quantity A |
Quantity B |
\(ab^2\) |
\(a^2b\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: ab^2
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22 Nov 2018, 09:01
22 Nov 2018, 09:01
1
Carcass wrote:
Quantity A |
Quantity B |
\(ab^2\) |
\(a^2b\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Let's test some different values of a and b
Case i: a = 1 and b = 1
We get:
Quantity A: ab² = (1)(1²) = 1
Quantity B: a²b = (1²)(1) = 1
In this case, Quantity A is EQUAL to Quantity B
Case ii: a = 2 and b = 1
We get:
Quantity A: ab² = (2)(1²) = 2
Quantity B: a²b = (2²)(1) = 4
In this case, Quantity B is GREATER THAN Quantity A
Answer: D
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Manager
Joined: 07 Aug 2016
Posts: 59
Given Kudos: 0
GRE 1: Q166 V156
Re: ab^2
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23 Nov 2018, 09:25
23 Nov 2018, 09:25
2
Carcass wrote:
Quantity A |
Quantity B |
\(ab^2\) |
\(a^2b\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Without any further details this is usually D. We don’t have any constraints or conditions.
Let a = -1 and b = 1
This way -1 * 1 = -1 (quantity A)
Whereas (-1)^2 * 1 = 1 (quantity B)
This way B > A
If inversed where a = 1 and b = -1
It would be A > B
So answer choice D
