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The last digit of the positive even number n equals the last
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20 Apr 2018, 11:25
20 Apr 2018, 11:25
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Question Stats:
52% (00:34) correct
47% (00:45) wrong based on 40 sessions
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The last digit of the positive even number n equals the last digit of \(n^2\) . Which one of the following could be n ?
(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
Re: The last digit of the positive even number n equals the last
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08 May 2018, 04:04
08 May 2018, 04:04
what kind of question is this..completely went bouncer.
Re: The last digit of the positive even number n equals the last
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08 May 2018, 11:47
08 May 2018, 11:47
1
Expert Reply
You should stay calm and apply techniques useful for your goal.
If you use the answer choices to reach the solution the question is easy.
The stem says an even positive number so C and E are suddenly out.
Now n must match the last digit of \(n^2\)
12 = 144 ---- 2 and four. does not fit
14 = 196 ----- 4 and 6. does not match
16 = 4.096 ----- 6 and 6. Match. D is the answer.
You could recognize that \(6^2\) is always a number that ends in 6.
Hope this helps
Regards
If you use the answer choices to reach the solution the question is easy.
The stem says an even positive number so C and E are suddenly out.
Now n must match the last digit of \(n^2\)
12 = 144 ---- 2 and four. does not fit
14 = 196 ----- 4 and 6. does not match
16 = 4.096 ----- 6 and 6. Match. D is the answer.
You could recognize that \(6^2\) is always a number that ends in 6.
Hope this helps
Regards
GRE is all about learning from our mistakes and not repeating them, I can understand.
