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(4 – 5x)^2 = 1
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24 Apr 2018, 01:52
24 Apr 2018, 01:52
Expert Reply
00:00
Question Stats:
58% (01:05) correct
41% (00:40) wrong based on 58 sessions
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\((4 - 5x)^2 = 1\)
Quantity A |
Quantity B |
\((4 - 5x) + (4 - 5x)^2\) |
1 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for the right answer and solution.
Re: (4 – 5x)^2 = 1
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24 Apr 2018, 03:18
24 Apr 2018, 03:18
1
4-5x can be+1 or -1 as -1^2 = 1 or +1^2 = 1
if +1, then A is greater
if -1, B is greater hence the answer option.
if +1, then A is greater
if -1, B is greater hence the answer option.
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Re: (4 – 5x)^2 = 1
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13 Nov 2019, 06:43
13 Nov 2019, 06:43
3
Be careful, gagangm
If (4 - 5x)^2 = 1, then EITHER x = 1 OR x = 0.6
If x = 1, then (4 - 5x)^2 = [4 - 5(1)]^2 = [-1]^2 = 1
If x = 0.6, then (4 - 5x)^2 = [4 - 5(0.6)]^2 = [4 - 3]^2 [1]^2 = 1
Cheers,
Brent
If (4 - 5x)^2 = 1, then EITHER x = 1 OR x = 0.6
If x = 1, then (4 - 5x)^2 = [4 - 5(1)]^2 = [-1]^2 = 1
If x = 0.6, then (4 - 5x)^2 = [4 - 5(0.6)]^2 = [4 - 3]^2 [1]^2 = 1
Cheers,
Brent
