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Step 1: Rule out products of squaring. The square of any real number (meaning any value on the number line) cannot be negative. Since squaring is the final operation in (A), (B), and (C), those answer choices must work out to either zero or some positive value.
✗A. (x+y)2 ✗B. (x−y)2 ✗C. (y−x)2
Step 2: Assign values to x and y if you're unsure whether x2 or y2 is bigger. Neither x nor y is equal to zero, so both x2 and y2 are positive. If x2>y2, then (E) must be correct, since a smaller positive minus a larger positive must equal a negative.
Let x=2 and y=−1. ✗D. 22−(−1)2=4−1=3 ✓E. (−1)2−22=1−4=−3
Re: GRE Arithmetic If x is positive and -x < y < 0
[#permalink]
17 Jul 2018, 15:20
RBornPowerScore wrote:
If x is positive and −x<y<0, then which of the following must be negative?
A. (x+y)2 B. (x−y)2 C. (y−x)2 D. x2−y2 E. y2−x2
Amazing question.
Note : x is a positive number but negative x is greater than y, which is also negative. So, we can conclude that positive x is greater that the value of y.
Suppose ,
x = 10 and negative x = -10.
y = -5
Option E:
y2−x2 = (-5)^2 - ( 10)^2
= 25 -100
= -75
The best answer is E.
gmatclubot
Re: GRE Arithmetic If x is positive and -x < y < 0 [#permalink]