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GRE Math Challenge #68-If x is 1, 2, or 3 and y
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03 May 2015, 01:23
03 May 2015, 01:23
Expert Reply
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Question Stats:
46% (00:21) correct
53% (00:30) wrong based on 13 sessions
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If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many different possible values?
A. Three
B. Four
C. Five
D. Six
E. Seven
A. Three
B. Four
C. Five
D. Six
E. Seven
Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y
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12 Dec 2017, 11:13
12 Dec 2017, 11:13
sandy wrote:
If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many different possible values?
A. Three
B. Four
C. Five
D. Six
E. Seven
A. Three
B. Four
C. Five
D. Six
E. Seven
Here let us put the values of x and y and find different possible values
xy= 1 * 2 = 2
xy= 1 * 4 = 4
xy= 2 * 2 = 4
xy= 2 * 4 = 8
xy= 3 * 2 = 6
xy= 3 * 4 = 12
Hence there are 5 different values, because the value 4 appeared twice
Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y
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10 May 2018, 10:34
10 May 2018, 10:34
I think we can also add 3 x's and 2 y's to get the desired option... I think the question can also be solved by combinatronics. .Please clarify.
