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The average (arithmetic mean) of 12 and 20 is equal to the a

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Carcass
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The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink] New post   14 May 2018, 12:13
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The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

Quantity A
Quantity B
x
16


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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A
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink] New post   03 Aug 2018, 21:52
1
Carcass wrote:
The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

Quantity A
Quantity B
x
16


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



From the statement we can write as:

\(\frac{12 + 20}2 = \frac{15 + x}2\)

or \(x = 12 + 5 = 17\)

QTY A > QTY B
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink] New post   01 Oct 2019, 09:14
Carcass wrote:
The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

Quantity A
Quantity B
x
16



Given: The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x

We can write: \(\frac{12+20}{2} = \frac{15+x}{2}\)

Multiply both sides by 2 to get: \(12+20 = 15+x\)

Simplify to get: \(32 = 15+x\)

Solve: \(x = 17\)

we get:
Quantity A: 17
Quantity B: 16

Answer: A

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Brent
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink] New post   03 Aug 2022, 23:55
1
Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of All the values = Average * Total Number of Values

The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x

Average = \(\frac{Sum}{2}\)

The average (arithmetic mean) of 12 and 20 = The average (arithmetic mean) of 15 and x
=> \(\frac{12 + 20}{2}\) = \(\frac{15 + x}{2}\)
=> 32 = 15 + x
=> x = 32 - 15 = 17

Clearly, Quantity A (17) > Quantity B (16)

So, Answer will be A.
Hope it helps!

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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink]
03 Aug 2022, 23:55
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