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32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28
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19 May 2018, 12:26
19 May 2018, 12:26
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89% (00:19) correct
10% (00:47) wrong based on 85 sessions
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Re: 32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28
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13 May 2019, 04:54
13 May 2019, 04:54
sandy wrote:
\(\frac{32}{4 + 6 × 2}=\)
(A) 8/5
(B) 16/5
(C) 2
(D) 20
(E) 28
(A) 8/5
(B) 16/5
(C) 2
(D) 20
(E) 28
This is all about the order of operations
PEMDAS (aka BEDMAS) tells We must evaluate the stuff in the brackets first: \(4 + 6 × 2\)
We must also complete all multiplication before addition.
So, \(4 + 6 × 2 = 4 + 12 = 16\)
So, \(\frac{32}{4 + 6 × 2}=\frac{32}{16}=2\)
Answer: C
Cheers,
Brent
Re: 32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28
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14 Aug 2024, 20:37
14 Aug 2024, 20:37
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