GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Kate and Chad are planning their wedding dinner and must sel
[#permalink]
30 Dec 2017, 14:28
30 Dec 2017, 14:28
1
Expert Reply
2
Bookmarks
00:00
Question Stats:
87% (00:58) correct
12% (00:47) wrong based on 56 sessions
Hide Show timer Statistics
Kate and Chad are planning their wedding dinner and must select 3 of 12 entrees and 2 of 3 desserts for their guests to be able to choose from. How many different combinations of
offerings are possible?
offerings are possible?
Drill 2
Question: 6
Page: 563
Question: 6
Page: 563
Show: :: OA
660
Re: Kate and Chad are planning their wedding dinner and must sel
[#permalink]
08 Jan 2018, 16:31
08 Jan 2018, 16:31
Expert Reply
Explanation
The order of entrees the guests chose from does not matter.
Therefore, the number of different possibilities of entrees is \(\frac{12 \times 11 \times 10}{3 \times 2 \times 1}\)=220. The order of desserts does not matter
either, so there are \(\frac{3 \times 2}{2}\)=3 possible different combinations of desserts.
Multiplying the two together gives a total of 660 possible different combinations of offerings.
The order of entrees the guests chose from does not matter.
Therefore, the number of different possibilities of entrees is \(\frac{12 \times 11 \times 10}{3 \times 2 \times 1}\)=220. The order of desserts does not matter
either, so there are \(\frac{3 \times 2}{2}\)=3 possible different combinations of desserts.
Multiplying the two together gives a total of 660 possible different combinations of offerings.
Re: Kate and Chad are planning their wedding dinner and must sel
[#permalink]
23 Jan 2018, 11:17
23 Jan 2018, 11:17
1
12C3 * 3C2
660
660
