GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The length and width of a painted rectangle were each increa
[#permalink]
10 Jun 2018, 05:15
10 Jun 2018, 05:15
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
91% (00:44) correct
8% (00:57) wrong based on 92 sessions
Hide Show timer Statistics
The length and width of a painted rectangle were each increased by 10%.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The percent increase in the area of the painted rectangle |
10% |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: The length and width of a painted rectangle were each increa
[#permalink]
14 Jul 2018, 04:39
14 Jul 2018, 04:39
Expert Reply
Explanation
Choose smart numbers for the dimensions of the rectangle—for instance, length = 20 and width = 10.
The original area of the rectangle = length × width = 200. After a 10% increase for both the length and the width, the area becomes 22 × 11 = 242.
Use the formula for percent change:
Percent Change =\(\frac{Difference}{Original} \times 100\%\)=\(\frac{242-200}{200} \times 100\%=21\%\)
Quantity A is greater.
Alternatively, use logic. The formula for area requires multiplying the length and the width. If just one side is increased by 10%, then the overall area will increase by 10%. If two sides are increased by 10%, then the overall area will increase by more than 10%.
Choose smart numbers for the dimensions of the rectangle—for instance, length = 20 and width = 10.
The original area of the rectangle = length × width = 200. After a 10% increase for both the length and the width, the area becomes 22 × 11 = 242.
Use the formula for percent change:
Percent Change =\(\frac{Difference}{Original} \times 100\%\)=\(\frac{242-200}{200} \times 100\%=21\%\)
Quantity A is greater.
Alternatively, use logic. The formula for area requires multiplying the length and the width. If just one side is increased by 10%, then the overall area will increase by 10%. If two sides are increased by 10%, then the overall area will increase by more than 10%.
Re: The length and width of a painted rectangle were each increa
[#permalink]
01 May 2020, 04:30
01 May 2020, 04:30
Smart numbers to the rescue!
A square is a rectangle so I chose the same length and width.
Original length = 10
Original width = 10
Original area = 10*10 = 100
New length = 10+10% = 11
New width = 10+10% = 11
New area = 11*11 = 121
Using percent change formula: (new - old) / old --> (121-100) / 100 = 21/100 = 21%
21% is greater than 10%, therefore answer is A.
A square is a rectangle so I chose the same length and width.
Original length = 10
Original width = 10
Original area = 10*10 = 100
New length = 10+10% = 11
New width = 10+10% = 11
New area = 11*11 = 121
Using percent change formula: (new - old) / old --> (121-100) / 100 = 21/100 = 21%
21% is greater than 10%, therefore answer is A.
