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Re: a, b, and c are positive [#permalink]
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FatemehAsgarinejad wrote:
Answer: D
A: (a + b) % c
B: c % (a + b)
If a+b = c or : A and B are equal.
If a+b < c : A is equal to a+b and B is equal to c mod a+b. So B is bigger.
If a+b > c : A is equal to a+b mod c and B is equal to c. So A is bigger.

We can apply different values to see this as well.
The answer is D.


Lets examine by plugging values in this case a=10 b=30 and c=30

Quantity A is (20+30)% of 30 or \(\frac{50}{100} \times 30\)

Quantity B is 30% of (20+30) or \(\frac{30}{100} \times 50\)

See in both cases the numerator and the denominator is always the same i.e \(30 \times 50\) and \(100\) respectively.

The answer is indeed C.
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Re: a, b, and c are positive [#permalink]
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Explanation

It is always the case that, for two positive quantities, M% of N = N% of M. In this case, (a + b) makes the problem appear more complicated, but the principle still applies. Algebraically:

Quantity A : \(\frac{a+b}{100}\times c\)

Quantity B: \(\frac{c}{100}\times (a+b)\)


Both quantities can be simplified to \(\frac{(a+b) \times c}{100}\). The two quantities are equal.
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Re: a, b, and c are positive [#permalink]
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Re: a, b, and c are positive [#permalink]
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