GreenlightTestPrep wrote:
In a certain sequence, term1 = 64, and for all n > 1, termn = (2^n)(termn-1)
What is the value of term11/term8 ?
A) 2^3
B) 2^6
C) 2^9
D) 2^27
E) 2^30
*kudos for all correct solutions[/quote]
Let's list a few terms and
look for a patternterm
1 = 64 = 2^6
term
2 = (2^6)(2^2)
term
3 = (2^6)(2^2)(2^3)
term
4 = (2^6)(2^2)(2^3)(2^4)
.
.
.
term
8 =
(2^6)(2^2)(2^3)(2^4)(2^5)(2^6)(2^7)(2^8).
.
.
term
11 =
(2^6)(2^2)(2^3)(2^4)(2^5)(2^6)(2^7)(2^8)(2^9)(2^10)(2^11)
So, term11/term8 =
(2^6)(2^2)(2^3)(2^4)(2^5)(2^6)(2^7)(2^8)(2^9)(2^10)(2^11)
/(2^6)(2^2)(2^3)(2^4)(2^5)(2^6)(2^7)(2^8)= (2^9)(2^10)(2^11)
= 2^30
Answer: E
Cheers,
Brent