GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
QOTD#15 If |x^2y| = |(–w)z|, then which of the following
[#permalink]
Updated on: 08 Dec 2020, 10:57
Updated on: 08 Dec 2020, 10:57
1
Expert Reply
10
Bookmarks
00:00
Question Stats:
16% (01:47) correct
83% (01:48) wrong based on 71 sessions
Hide Show timer Statistics
If \(|x^2y| = |(-w)z|\), then which of the following could be true?
Indicate all possible values.
A. \(x^2 = wz\)
B. \(|x^2y| = - |(-w)z|\)
C. \(-(wz) = wz\)
D. \(|x^2| = |(-w)z|\)
E. \(-w = z\)
F. \(x^2 = -|y|\)
Indicate all possible values.
A. \(x^2 = wz\)
B. \(|x^2y| = - |(-w)z|\)
C. \(-(wz) = wz\)
D. \(|x^2| = |(-w)z|\)
E. \(-w = z\)
F. \(x^2 = -|y|\)
Drill 4
Question: 9
Page: 294
Question: 9
Page: 294
ShowHide Answer
Official Answer
A,C,D,E
Re: QOTD#15 If |x^2y| = |(–w)z|, then which of the following
[#permalink]
20 Nov 2016, 10:07
20 Nov 2016, 10:07
Expert Reply
Explanation
The best way to approach a could be question is to consider many different kinds of numbers to plug in that could work in the problem. We will have to plug in a few times here, so let’s start with easy numbers. For instance, let’s try making every variable in the problem equal to 1.
Immediately, choices (A) and (D) work. If we made w = 1 and z = −1, then choice (E) works as well. Try plugging in 0 for either w or z and choice (C) can also work. In the end, choices (B) and (F) are always going to have a positive value on the left side of the equation and a negative value on the right, and therefore will not be correct. An absolute value is always positive, so it can never equal something negative.
Hence option A, C, D, and E are correct.
The best way to approach a could be question is to consider many different kinds of numbers to plug in that could work in the problem. We will have to plug in a few times here, so let’s start with easy numbers. For instance, let’s try making every variable in the problem equal to 1.
Immediately, choices (A) and (D) work. If we made w = 1 and z = −1, then choice (E) works as well. Try plugging in 0 for either w or z and choice (C) can also work. In the end, choices (B) and (F) are always going to have a positive value on the left side of the equation and a negative value on the right, and therefore will not be correct. An absolute value is always positive, so it can never equal something negative.
Hence option A, C, D, and E are correct.
Re: QOTD#15 If |x^2y| = |(–w)z|, then which of the following
[#permalink]
26 Aug 2017, 09:59
26 Aug 2017, 09:59
2
Actually if you plug in 0 for all variables all of the answers are correct. Am I missing something here?
