GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Area of circle with radius [square_root]7[/square_root]
[#permalink]
21 Jun 2018, 02:21
21 Jun 2018, 02:21
2
00:00
Question Stats:
90% (00:33) correct
9% (00:18) wrong based on 41 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
Area of circle with radius \(\sqrt{7}\) |
Area of circle with diameter \(\sqrt{14}\) |
A The quantity in Column A is greater
B The quantity in Column B is greater
C The two quantities are equal
D The relationship cannot be determined from the information given
Re: Area of circle with radius [square_root]7[/square_root]
[#permalink]
22 Jun 2018, 07:38
22 Jun 2018, 07:38
1
amorphous wrote:
Quantity A |
Quantity B |
Area of circle with radius \(\sqrt{7}\) |
Area of circle with diameter \(\sqrt{14}\) |
For statement 1,
We know area of the circle = π \(r^2\)
= π \((\sqrt{7})^2\)
= 7π
In Statement 2,
We know area of the circle = π \(r^2\)
= π \((\sqrt{14})/2)^2\) (Since here diameter is given so we divide it by 2 to get the radius)
= \(\frac{14}{4}\) π
= \(\frac{7}{2}\) π, which is less than statement 1
Hence option A
Re: Area of circle with radius [square_root]7[/square_root]
[#permalink]
19 Jan 2019, 10:25
19 Jan 2019, 10:25
B has radius sqrt14/2<sqrt7
that gives area A> area B
that gives area A> area B
