GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If h(x) = |3x| + 2 and g(x) = x2 – 7 and g(m) = 29, what is
[#permalink]
30 Jul 2018, 09:55
30 Jul 2018, 09:55
Expert Reply
1
Bookmarks
00:00
Question Stats:
96% (00:47) correct
3% (03:16) wrong based on 27 sessions
Hide Show timer Statistics
If \(h(x) = |3x| + 2\) and \(g(x) = x^2 - 7\) and \(g(m) = 29\), what is the value of \(h(m)\)?
Show: :: OA
20
Re: If h(x) = |3x| + 2 and g(x) = x2 – 7 and g(m) = 29, what is
[#permalink]
02 Aug 2018, 06:41
02 Aug 2018, 06:41
Expert Reply
Explanation
The problem introduces two functions as well as the fact that g(m) = 29. First, solve for m:
\(g(m) = m^2 - 7 = 29\)
\(m^2 = 36\)
\(m = 6\) or \(-6\)
The question asks for h(m):
\(h(6) = |3 \times 6| + 2 = |18| + 2 = 18 + 2 = 20\)
\(h(-6) = |3 \times -6| + 2 = |-18| + 2 = 18 + 2 = 20\)
The answer is 20 for either value of m.
The problem introduces two functions as well as the fact that g(m) = 29. First, solve for m:
\(g(m) = m^2 - 7 = 29\)
\(m^2 = 36\)
\(m = 6\) or \(-6\)
The question asks for h(m):
\(h(6) = |3 \times 6| + 2 = |18| + 2 = 18 + 2 = 20\)
\(h(-6) = |3 \times -6| + 2 = |-18| + 2 = 18 + 2 = 20\)
The answer is 20 for either value of m.
Re: If h(x) = |3x| + 2 and g(x) = x2 7 and g(m) = 29, what is
[#permalink]
18 Dec 2022, 13:22
18 Dec 2022, 13:22
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
