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BurgerTown offers many options for customizing a burger. The
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30 Jul 2018, 10:44
30 Jul 2018, 10:44
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Question Stats:
41% (01:10) correct
58% (01:39) wrong based on 85 sessions
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BurgerTown offers many options for customizing a burger. There are 3 types of meats and 7 condiments: lettuce, tomatoes, pickles, onions, ketchup, mustard, and special sauce. A burger must include meat, but may include as many or as few condiments as the customer wants. How many different burgers are possible?
(A) \(8!\)
(B) \((3)(7!)\)
(C) \((3)(8!)\)
(D) \((8)(2^7)\)
(E) \((3)(2^7)\)
(A) \(8!\)
(B) \((3)(7!)\)
(C) \((3)(8!)\)
(D) \((8)(2^7)\)
(E) \((3)(2^7)\)
Re: BurgerTown offers many options for customizing a burger. The
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07 Aug 2018, 06:09
07 Aug 2018, 06:09
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Explanation
This problem tests the fundamental counting principle, which states that the total number of choices is equal to the product of the independent choices. The key to this problem is realizing how many choices there are for each option. For the meat, there are 3 choices.
For each of the condiments there are exactly 2 choices: yes or no. The only real choice regarding each condiment is whether to include it at all. As there are 7 condiments, the total number of choices is \((3)(2)(2)(2)(2)(2)(2)(2) = (3)(2^7)\).
Note: the condiment options cannot be counted as 8! (0 through 7 = 8 options) because, in this case, the order in which the options are chosen does not matter; a burger with lettuce and pickles is the same as a burger with pickles and lettuce.
This problem tests the fundamental counting principle, which states that the total number of choices is equal to the product of the independent choices. The key to this problem is realizing how many choices there are for each option. For the meat, there are 3 choices.
For each of the condiments there are exactly 2 choices: yes or no. The only real choice regarding each condiment is whether to include it at all. As there are 7 condiments, the total number of choices is \((3)(2)(2)(2)(2)(2)(2)(2) = (3)(2^7)\).
Note: the condiment options cannot be counted as 8! (0 through 7 = 8 options) because, in this case, the order in which the options are chosen does not matter; a burger with lettuce and pickles is the same as a burger with pickles and lettuce.
General Discussion
Re: BurgerTown offers many options for customizing a burger. The
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05 Aug 2018, 21:37
05 Aug 2018, 21:37
sandy wrote:
BurgerTown offers many options for customizing a burger. There are 3 types of meats and 7 condiments: lettuce, tomatoes, pickles, onions, ketchup, mustard, and special sauce. A burger must include meat, but may include as many or as few condiments as the customer wants. How many different burgers are possible?
(A) 8!
(B) (3)(7!)
(C) (3)(8!)
(D) (8)(27)
(E) (3)(27)
(A) 8!
(B) (3)(7!)
(C) (3)(8!)
(D) (8)(27)
(E) (3)(27)
Answer is (3)(28). Please confirm and provide explanation.
