Last visit was: 18 Dec 2024, 02:56 It is currently 18 Dec 2024, 02:56

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30352
Own Kudos [?]: 36747 [2]
Given Kudos: 26080
Send PM
Most Helpful Community Reply
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2280 [5]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
General Discussion
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2280 [3]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
Intern
Intern
Joined: 05 Feb 2024
Posts: 26
Own Kudos [?]: 17 [0]
Given Kudos: 151
Send PM
Carla is having a dinner party and is inviting 5 guests: 3 b [#permalink]
I am facing some issues. My approach was the following -

Carla is hosting a dinner party with 5 guests and herself, making a total of 6 people. She will sit at the head of the table, leaving 5 seats for her guests. The constraint is that no two guests of the same gender can sit next to each other. This means the seating arrangement must alternate genders.

There are two possible gender arrangements for the guests around the table:

1. Boy, Girl, Boy, Carla, Boy, Girl (BGBCBG)
2. Girl, Boy, Carla, Boy, Girl, Boy (GBCBGB)

For each of these arrangements, we can calculate the number of ways the guests can be seated based on their gender.

Assume Carla is fixed

**For arrangement 1 (BGBCBG):**

- There are 3 boys and 2 girls.
- For the first slot for a boy, there are 3 choices (3 boys).
- For the first slot for a girl, there are 2 choices (2 girls).
- For the second slot for a boy, there are 2 choices (the remaining 2 boys).
- For the second slot for a girl, there is 1 choice (the remaining girl).
- For the third slot for a boy, there is 1 choice (the remaining boy).

This gives us \(3 \times 2 \times 2 \times 1 \times 1 = 12\) arrangements for the first scenario.

**For arrangement 2 (GBCBGB):**

- For the first slot for a girl, there are 2 choices (2 girls).
- For the first slot for a boy, there are 3 choices (3 boys).
- For the second slot for a girl, there is 1 choice (the remaining girl).
- For the second slot for a boy, there are 2 choices (the remaining 2 boys).
- For the third slot for a boy, there is 1 choice (the remaining boy).

This would also give us \(2 \times 3 \times 1 \times 2 \times 1 = 12\) arrangements for the second scenario.

i.e. a total = 24

One of these is the reverse of the other one, but since order matters. Won't both of these orders be correct?

I know I'm wrong, but what's the fundamental flaw in my reasoning? I'm not able to understand. Can you please help me figure that part out?
Prep Club for GRE Bot
Carla is having a dinner party and is inviting 5 guests: 3 b [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne