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g(x) = x2 – 4 and g(c) = 12. If c < 0, what is the value of
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30 Jul 2018, 09:52
30 Jul 2018, 09:52
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Question Stats:
81% (00:48) correct
18% (01:11) wrong based on 38 sessions
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Re: g(x) = x2 – 4 and g(c) = 12. If c < 0, what is the value of
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02 Aug 2018, 06:37
02 Aug 2018, 06:37
2
Expert Reply
Explanation
For the function \(g(x) = x^2 - 4\), plugging c in for x gives the answer 12. Thus:
\(c^2 - 4 = 12\)
\(c^2 = 16\)
\(c = 4\) or \(-4\)
The problem indicates that c < 0, so c must be –4.
The problem then asks for \(g(c - 2)\). Since \(c = -4\), \(c - 2 = -6\).
Plug –6 into the function:
\(g(-6) = (-6)^2 - 4\)
\(g(-6) = 36 - 4 = 32\)
For the function \(g(x) = x^2 - 4\), plugging c in for x gives the answer 12. Thus:
\(c^2 - 4 = 12\)
\(c^2 = 16\)
\(c = 4\) or \(-4\)
The problem indicates that c < 0, so c must be –4.
The problem then asks for \(g(c - 2)\). Since \(c = -4\), \(c - 2 = -6\).
Plug –6 into the function:
\(g(-6) = (-6)^2 - 4\)
\(g(-6) = 36 - 4 = 32\)
Re: g(x) = x2 4 and g(c) = 12. If c < 0, what is the value of
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23 Oct 2022, 09:48
23 Oct 2022, 09:48
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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