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A bag contains 6 black chips numbered 1–6 respectively and 6
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05 Aug 2018, 14:27
05 Aug 2018, 14:27
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Question Stats:
85% (00:52) correct
14% (01:01) wrong based on 34 sessions
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A bag contains 6 black chips numbered 1–6 respectively and 6 white chips numbered 1–6 respectively. If Pavel reaches into the bag of 12 chips and removes 2 chips, one after the other,
without replacing them, what is the probability that he will pick black chip #3 and then white chip #3?
Give your answer as a fraction.
without replacing them, what is the probability that he will pick black chip #3 and then white chip #3?
Give your answer as a fraction.
Show: :: OA
\(\frac{1}{132}\)
Re: A bag contains 6 black chips numbered 1–6 respectively and 6
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07 Aug 2018, 06:20
07 Aug 2018, 06:20
1
Expert Reply
Explantion
The probability of picking black chip #3 is \(\frac{1}{12}\). Once Pavel has removed the first chip, only 11 chips remain, so the probability of picking white chip #3 is \(\frac{1}{11}\). Multiply \(\frac{1}{12}\times\frac{1}{11}=\frac{1}{132}\).
The probability of picking black chip #3 is \(\frac{1}{12}\). Once Pavel has removed the first chip, only 11 chips remain, so the probability of picking white chip #3 is \(\frac{1}{11}\). Multiply \(\frac{1}{12}\times\frac{1}{11}=\frac{1}{132}\).
Re: A bag contains 6 black chips numbered 1–6 respectively and 6
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04 Oct 2019, 14:32
04 Oct 2019, 14:32
1/132
