Explanation

Because this is an “at least” question, use the 1 – x shortcut:

(The probability of picking at least one man) + (The probability of picking no men) = 1

The probability of picking no men is an and setup: woman and woman and woman.

For the first choice, there are 8 women out of 10 people: $\frac{8}{10}=\frac{4}{5}$.

For the second choice, there are $\frac{7}{9}$(because one woman has already been chosen).

For the third choice, there are $\frac{6}{8}=\frac{3}{4}$.

Multiply the three probabilities together to find the probability that the committee will be comprised of woman and woman and woman:

$\frac{4}{5} \times \frac{7}{9} \times \frac{3}{4}=\frac{7}{15}$.

To determine the probability of picking at least one man, subtract this result from 1:

$1- \frac{7}{15}=\frac{8}{15}$.