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If |3x + 7| ≥ 2x + 12, then which of the following is true?
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08 Aug 2018, 16:28
08 Aug 2018, 16:28
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Question Stats:
61% (01:23) correct
38% (01:49) wrong based on 187 sessions
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If \(|3x + 7| ≥ 2x + 12\), then which of the following is true?
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
Re: If |3x + 7| ≥ 2x + 12, then which of the following is true?
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09 Aug 2018, 14:06
09 Aug 2018, 14:06
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Carcass wrote:
If \(|3x + 7| ≥ 2x + 12\), then which of the following is true?
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
For absolute value there will be 2 cases all time.
Case 1 : when 3x + 7 is positive.
\(3x + 7 \geq2x + 12\)
\(x \geq5\)
Case 2: When 3x + 7 is negative.
\(-3x - 7 \geq2x + 12\)
\(x \leq-19/5.\)
The best answer is D.
General Discussion
Re: If |3x + 7| ≥ 2x + 12, then which of the following is true?
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04 Mar 2020, 14:34
04 Mar 2020, 14:34
For some reason I keep getting X less than or equal to -19/5 when I make the right side negative and add the variables to get +5. Why does thi shappen?
