Last visit was: 23 Dec 2024, 05:16 It is currently 23 Dec 2024, 05:16

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30484
Own Kudos [?]: 36833 [2]
Given Kudos: 26100
Send PM
Manager
Manager
Joined: 06 Jun 2018
Posts: 102
Own Kudos [?]: 124 [0]
Given Kudos: 4
Send PM
avatar
Intern
Intern
Joined: 10 Oct 2017
Posts: 9
Own Kudos [?]: 6 [0]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 20 Feb 2020
Posts: 5
Own Kudos [?]: 2 [1]
Given Kudos: 0
Send PM
Re: |x| + |y| > |x + z| [#permalink]
1
Bookmarks
fixzion wrote:
General formula : |a|+|b|≥|a+b|
is this a formula for every value we put in? thanks


Yes, and the two sides are equal only if a and b are both non negatives, Otherwise, if ab<0 then |a|+|b|>|a+b|
avatar
Intern
Intern
Joined: 12 Sep 2020
Posts: 15
Own Kudos [?]: 9 [1]
Given Kudos: 0
Send PM
Re: |x| + |y| > |x + z| [#permalink]
1
In case someone is not aware of the property, they can do this:

Take x = 0,

Then you have |y| > |z|

Now its clearly seen, y can be lesser and greater than z, since only the absolute of y is greater than z.
avatar
Intern
Intern
Joined: 10 May 2019
Posts: 3
Own Kudos [?]: 1 [1]
Given Kudos: 0
Send PM
Re: |x| + |y| > |x + z| [#permalink]
1
Normally, when more than two variables are involved in an equality and you do not have sufficient information to deduce your answer, it is best to try and plug in values and see the answer for yourself. Always start with the simplest values :-
1) Put x = 0, y = 1 and z = 0. In this case, |0| + |1| > |0 + 0| i.e. |1| > |0|. Thus y > z.
1) Put x = 0, y = -1 and z = 0. In this case, |0| + |-1| > |0 + 0| i.e. |1| > |0|. Thus y < z.

Thus, D is the answer.
Prep Club for GRE Bot
Re: |x| + |y| > |x + z| [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne