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If |x+4|/2>5 and x<0, which of the following could be the va
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08 Aug 2018, 16:09
08 Aug 2018, 16:09
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Question Stats:
57% (00:40) correct
42% (00:51) wrong based on 137 sessions
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If \(\frac{|x+4|}{2}>5\) and \(x<0\), which of the following could be the value of x?
Indicate all such values
A. -6
B. -14
C. -18
Indicate all such values
A. -6
B. -14
C. -18
Re: If |x+4|/2>5 and x<0, which of the following could be the va
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11 Aug 2018, 12:16
11 Aug 2018, 12:16
1
Simple case of solving an inequality, given our constraint that x < 0.
|x+4|/2 > 5
Multiply both sides by 2
|x+4| > 10
Here we have two cases:
x+4 > 10
or
x+4 < -10
In both cases we subtract both sides by 4
x > 6
or
x < -14
Only the second inequality fits the constraint that x < 0
And only C is correct if x < -14 (note that it's strictly less than -14, not less than or equal to).
|x+4|/2 > 5
Multiply both sides by 2
|x+4| > 10
Here we have two cases:
x+4 > 10
or
x+4 < -10
In both cases we subtract both sides by 4
x > 6
or
x < -14
Only the second inequality fits the constraint that x < 0
And only C is correct if x < -14 (note that it's strictly less than -14, not less than or equal to).
Re: If |x+4|/2>5 and x<0, which of the following could be the va
[#permalink]
05 Mar 2020, 14:25
05 Mar 2020, 14:25
Romang67 wrote:
Simple case of solving an inequality, given our constraint that x < 0.
|x+4|/2 > 5
Multiply both sides by 2
|x+4| > 10
Here we have two cases:
x+4 > 10
or
x+4 < -10
In both cases we subtract both sides by 4
x > 6
or
x < -14
Only the second inequality fits the constraint that x < 0
And only C is correct if x < -14 (note that it's strictly less than -14, not less than or equal to).
|x+4|/2 > 5
Multiply both sides by 2
|x+4| > 10
Here we have two cases:
x+4 > 10
or
x+4 < -10
In both cases we subtract both sides by 4
x > 6
or
x < -14
Only the second inequality fits the constraint that x < 0
And only C is correct if x < -14 (note that it's strictly less than -14, not less than or equal to).
So when we set the 10 to negative we have to flip the inequality sign?
