GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
At a certain college, the ratio of students to professors is
[#permalink]
19 Aug 2018, 03:03
19 Aug 2018, 03:03
Expert Reply
1
Bookmarks
00:00
Question Stats:
81% (01:07) correct
18% (01:23) wrong based on 138 sessions
Hide Show timer Statistics
At a certain college, the ratio of students to professors is 8 : 1 and the ratio of students to administrators is 5 : 2. No person is in more than one category (for instance, there are no administrators who are also students).
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The fractional ratio of professors to administrators |
\(\frac{5}{8}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
At a certain college, the ratio of students to professors is
[#permalink]
20 Aug 2018, 07:33
20 Aug 2018, 07:33
1
sandy wrote:
At a certain college, the ratio of students to professors is 8 : 1 and the ratio of students to administrators is 5 : 2. No person is in more than one category (for instance, there are no administrators who are also students).
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The fractional ratio of professors to administrators |
\(\frac{5}{8}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Notice that the number of students is common to BOTH ratios
Ratio of students to professors is 8 : 1
So, S : P = 8 : 1
Ratio of students to administrators is 5 : 2
So, S : A = 5 : 2
In order to COMBINE the two ratios, we must find EQUIVALENT ratios such that we have the same number of students in each ratio.
Take: 8 : 1 and multiply both sides by 5 to get the EQUIVALENT ratio: S : P = 40 : 5
Next, take: 5 : 2 and multiply both sides by 8 to get the EQUIVALENT ratio: S : A = 40 : 16
We can now COMBINE the two ratios to get: S : P : A = 40 : 5 : 16
We have:
Quantity A: P/A (aka P : A)
Quantity B: 5/8
From our ratio S : P : A = 40 : 5 : 16, we can see that P/A = 5/16
So, we have:
Quantity A: 5/16
Quantity B: 5/8
So, Quantity B is greater.
Answer: B
Re: At a certain college, the ratio of students to professors is
[#permalink]
09 Sep 2021, 20:05
09 Sep 2021, 20:05
Student : Professor = 8:1 = 40:5
Student : Administrator = 5:2 = 40:16
As student ratio is common, we can write=> Professor : Administrator = 5:16, which is less than 5/8.
So ans: B
Student : Administrator = 5:2 = 40:16
As student ratio is common, we can write=> Professor : Administrator = 5:16, which is less than 5/8.
So ans: B
