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If the width of a rectangle is w, the length is l, the perim
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19 Aug 2018, 04:12
19 Aug 2018, 04:12
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Question Stats:
82% (01:51) correct
17% (01:43) wrong based on 34 sessions
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If the width of a rectangle is w, the length is l, the perimeter is p, and w = 2l, what is the area in terms of p?
(A) \(\frac{p^2}{18}\)
(B) \(\frac{p^2}{36}\)
(C) \(\frac{p}{9}\)
(D) \(\frac{p^2}{9}\)
(E) \(\frac{p}{6}\)
(A) \(\frac{p^2}{18}\)
(B) \(\frac{p^2}{36}\)
(C) \(\frac{p}{9}\)
(D) \(\frac{p^2}{9}\)
(E) \(\frac{p}{6}\)
Re: If the width of a rectangle is w, the length is l, the perim
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21 Aug 2018, 22:46
21 Aug 2018, 22:46
2
We can use Plugging-in technique for this question.
We have given w=2L, so let's plug 2 for L. i.e L=2. so W=4, P=12, A=8.
For option A (12*12)/18 the answer is 8 which is our target answer. Verify for other options too. You might end up with different values for A.
Hope it helps!
We have given w=2L, so let's plug 2 for L. i.e L=2. so W=4, P=12, A=8.
For option A (12*12)/18 the answer is 8 which is our target answer. Verify for other options too. You might end up with different values for A.
Hope it helps!
Re: If the width of a rectangle is w, the length is l, the perim
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08 Apr 2024, 10:40
08 Apr 2024, 10:40
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
