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216 = 2^x3^y x and y are integers.
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25 Aug 2018, 14:55
25 Aug 2018, 14:55
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\(216 = 2^x3^y\)
x and y are integers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
x and y are integers.
Quantity A |
Quantity B |
x |
y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: 216 = 2^x3^y x and y are integers.
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29 Aug 2018, 07:30
29 Aug 2018, 07:30
sandy wrote:
\(216 = 2^x3^y\)
x and y are integers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
x and y are integers.
Quantity A |
Quantity B |
x |
y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
This questions begs for some prime factorization
216 = (2)(2)(2)(3)(3)(3)
= (2^3)(3^3)
This means: (2^3)(3^3) = (2^x)(3^y)
At this point, we can see that x = 3 and y = 3
In other words, Quantity A = Quantity B
Answer: C
Cheers,
Brent
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Re: 216 = 2^x3^y x and y are integers.
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23 Feb 2023, 18:20
23 Feb 2023, 18:20
1
My approach was playing with numbers - I tried seeing if I could get a case where I could make X and Y the same and landed on 3. More lucky than anything else. I will prime factor next time.
