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If 5,000 = 2^x5^y and x and y are integers, what is the
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25 Aug 2018, 15:08
25 Aug 2018, 15:08
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Question Stats:
100% (00:47) correct
0% (00:00) wrong based on 48 sessions
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Re: If 5,000 = 2^x5^y and x and y are integers, what is the
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04 Sep 2018, 11:08
04 Sep 2018, 11:08
1
sandy wrote:
This calls for some prime factorization
5000 = (2)(2)(2)(5)(5)(5)(5)
= (2^3)(5^4)
So, we can write: (2^3)(5^4) = (2^x)(5^y)
We can see that x = 3 and y = 4
This means x + y = 3 + 4 = 7
Answer: 7
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Re: If 5,000 = 2^x5^y and x and y are integers, what is the
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25 Jan 2021, 01:44
25 Jan 2021, 01:44
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