Last visit was: 23 Nov 2024, 05:05 It is currently 23 Nov 2024, 05:05

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4813
Own Kudos [?]: 11196 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
avatar
Intern
Intern
Joined: 28 Aug 2018
Posts: 28
Own Kudos [?]: 36 [0]
Given Kudos: 0
GRE 1: Q170 V166
WE:Other (Education)
Send PM
avatar
Intern
Intern
Joined: 27 Aug 2018
Posts: 36
Own Kudos [?]: 30 [0]
Given Kudos: 0
Send PM
avatar
Manager
Manager
Joined: 02 Mar 2020
Posts: 54
Own Kudos [?]: 14 [0]
Given Kudos: 0
Send PM
Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
1
This is an example of how ETS will try to get you to combine variables for a mean and then forget that each is a separate value. a+b+c = 19... ok... a+b+c+13 = 19+13. In taking the mean here DIVIDE BY 4. Many will accidentally divide by 2 and end up answering wrong.
Moderator
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1111
Own Kudos [?]: 964 [0]
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Send PM
Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
Theory

    ➡ Average = Sum of all the Values / Total Number of Values

The average (arithmetic mean) of a, b, c, 5, and 6 is 6

Average = \(\frac{Sum}{5}\) = \(\frac{a + b + c + 5 + 6 }{5}\) = \(\frac{a + b + c + 11}{5}\) = 6 (given)
a + b + c + 11 = 6*5 = 30
=> a + b + c = 30 - 11 = 19

The average of a, b, c, and 13

Average = \(\frac{Sum}{4}\) = \(\frac{a + b + c + 13 }{4}\) = \(\frac{19 + 13}{4}\) = \(\frac{32}{4}\) = 8

So, Answer will be A.
Hope it helps!

Watch the following video to Learn the Basics of Statistics

Prep Club for GRE Bot
Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne