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The positive integer a is divisible by 2 and 0 < ab < 1.
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02 Sep 2018, 07:29
02 Sep 2018, 07:29
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60% (01:04) correct
39% (00:57) wrong based on 94 sessions
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The positive integer a is divisible by 2 and 0 < ab < 1.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
b |
\(\frac{1}{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: The positive integer a is divisible by 2 and 0 < ab < 1.
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22 Jan 2019, 07:44
22 Jan 2019, 07:44
2
Given that,
a = positive integer and divisible by 2. Hence. a = positive even numbers
ab < 1 and ab > 0, hence, b must be a fraction.
Now,
if b = 1/2 and a = 2, then, ab = 2*1/2 = 1 , this doesn't satisfy the given condition.Hence, option C is omitted.
If b = 1/4 and a = 2, then ab = 2 * 1/4 = 1/2, this will satisfy the given condition.
Hence, b = 1/4 which is less than 1/2 and answer is B.
a = positive integer and divisible by 2. Hence. a = positive even numbers
ab < 1 and ab > 0, hence, b must be a fraction.
Now,
if b = 1/2 and a = 2, then, ab = 2*1/2 = 1 , this doesn't satisfy the given condition.Hence, option C is omitted.
If b = 1/4 and a = 2, then ab = 2 * 1/4 = 1/2, this will satisfy the given condition.
Hence, b = 1/4 which is less than 1/2 and answer is B.
Re: The positive integer a is divisible by 2 and 0 < ab < 1.
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22 Jan 2019, 08:15
22 Jan 2019, 08:15
2
Expert Reply
sandy wrote:
The positive integer a is divisible by 2 and 0 < ab < 1.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
b |
\(\frac{1}{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let us try to find the maximum value of b, and for that we have to take the least value of a.
Since a is a positive integer and even, 2 is the least value of a. Therefore least value of ab is 2b, so 0 < ab < 1 means 0 < 2b < 1 or \(0<b<\frac{1}{2}\). Thus A<B
B
