GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
DBC + BCD or 90
[#permalink]
Updated on: 28 Nov 2018, 06:28
Updated on: 28 Nov 2018, 06:28
Expert Reply
00:00
Question Stats:
87% (00:47) correct
12% (00:01) wrong based on 16 sessions
Hide Show timer Statistics
Attachment:
triangle.jpg [ 9.24 KiB | Viewed 1826 times ]
\(AD=BD=6\), \(\angle ADB = 90°\)
Quantity A |
Quantity B |
\(\angle DBC+ \angle BCD\) |
\(90°\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Re: DBC + BCD or 90
[#permalink]
03 Nov 2018, 18:12
03 Nov 2018, 18:12
1
Carcass wrote:
Attachment:
triangle.jpg
\(AB=BD=6\), \(\angle ABD = 90°\)
Quantity A |
Quantity B |
\(\angle DBC+ \angle BCD\) |
\(90°\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Since \(\angle ADB = 90°\), therefore\(\angle BDC = 90°\)
Now in \(\triangle DBC\), we have
\(\angle BDC = 90°\)
and as the sum of angles in a \(\triangle\)add up to 180°
therefore
\(\angle DBC+ \angle BCD = 90°\)
Hence option C
Re: DBC + BCD or 90
[#permalink]
03 Nov 2018, 22:18
03 Nov 2018, 22:18
Expert Reply
Carcass wrote:
Attachment:
triangle.jpg
\(AB=BD=6\), \(\angle ABD = 90°\)
Quantity A |
Quantity B |
\(\angle DBC+ \angle BCD\) |
\(90°\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Ofcourse there is a typo as \(\angle ABD = 90°\) should be \(\angle ADB = 90°\)
now by the property of an exterior angle in a triangle, it is equal to the sum of opposite angles, so
\(\angle ADB = 90°=\angle DBC+ \angle BCD\)=A=90=B
C
Actually irrespective of AD=BD or not the answer will be C.
A poor question with wrong equivalence etc
Pl relook into the source.
