We know that a diagonal of a parallelogram cuts the parallelogram into two triangles of equal area.

Since BD is a diagonal of parallelogram ABCD, the area of the parallelogram equals twice the area of either of the two equal triangles ∆ABD or ∆DBC.

Hence, Column A = 2(area of ∆DBC). Similarly, since BC is a diagonal of parallelogram BECD, the area of the parallelogram BECD is 2(area of ∆DBC).

Thus, both columns equal 2(area of ∆DBC), and the answer is (C)

Since the base and height of both the parallelograms is same, their are is same.