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x > 0
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18 Sep 2018, 10:27
18 Sep 2018, 10:27
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Question Stats:
82% (00:21) correct
17% (00:20) wrong based on 67 sessions
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\(x > 0\)
Quantity A |
Quantity B |
\(x^3 + 1\) |
\(x^4 + 1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: x > 0
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18 Sep 2018, 15:49
18 Sep 2018, 15:49
1
Carcass wrote:
\(x > 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(x^3 + 1\) |
\(x^4 + 1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
We can solve this question using matching operations
Given:
Quantity A: x^3 + 1
Quantity B: x^4 + 1
Subtract 1 from both quantities to get:
Quantity A: x^3
Quantity B: x^4
Since x is POSITIVE, we know that x^3 is POSITIVE.
So, we can safely divide both quantities by x^3 to get:
Quantity A: 1
Quantity B: x
We know that x > 0.
This means x COULD equal 8, in which case, Quantity B is greater
Or x COULD equal 0.5, in which case, Quantity A is greater
x COULD also equal 1, in which case, the quantities are equal
Answer: D
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Re: x > 0
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02 Jan 2022, 07:32
02 Jan 2022, 07:32
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