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ab2c3 > 0 a2b2c3 < 0
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18 Sep 2018, 04:33
18 Sep 2018, 04:33
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Question Stats:
64% (00:46) correct
35% (01:01) wrong based on 78 sessions
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\(ab^2c^3 > 0\)
\(a^2b^2c^3 < 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
How to approach this question?
\(a^2b^2c^3 < 0\)
Quantity A |
Quantity B |
\(ab^2\) |
\(ac\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
How to approach this question?
Re: ab2c3 > 0 a2b2c3 < 0
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18 Sep 2018, 04:46
18 Sep 2018, 04:46
the first inequality is true if a<0 & c<0 or a>0 & c>0.
second inequality is true if c<0.
that's why it must be that a<0.
so we have a<0, b^2>0, and c<0.
thus the answer is B.
second inequality is true if c<0.
that's why it must be that a<0.
so we have a<0, b^2>0, and c<0.
thus the answer is B.
Re: ab2c3 > 0 a2b2c3 < 0
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18 Sep 2018, 04:54
18 Sep 2018, 04:54
saifee wrote:
the first inequality is true if a<0 & c<0 or a>0 & c>0.
second inequality is true if c<0.
that's why it must be that a<0.
so we have a<0, b^2>0, and c<0.
thus the answer is B.
second inequality is true if c<0.
that's why it must be that a<0.
so we have a<0, b^2>0, and c<0.
thus the answer is B.
I did not understand this - > "that's why it must be that a<0"
