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T > x, y < m, x < y
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24 Sep 2018, 03:21
24 Sep 2018, 03:21
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\(T > x\)
\(y < m\)
\(x < y\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(y < m\)
\(x < y\)
Quantity A |
Quantity B |
x+y |
T+m |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Joined: 10 Apr 2015
Posts: 6218
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Re: T > x, y < m, x < y
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24 Sep 2018, 10:17
24 Sep 2018, 10:17
1
Carcass wrote:
\(T > x\)
\(y < m\)
\(x < y\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(y < m\)
\(x < y\)
Quantity A |
Quantity B |
x+y |
T+m |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Let's makes some conclusions based on the given info.
y < m: So, m = some number that's greater than y
T > x: So, T = some number that's greater than x
We get:
Quantity A: y + x
Quantity B: (some number that's greater than y) + (some number that's greater than x)
When we compare the quantities in parts, we can see that Quantity B must be greater than Quantity A
Answer: B
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Joined: 23 Jan 2021
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Re: T > x, y < m, x < y
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27 May 2021, 21:26
27 May 2021, 21:26
1
Just add two quantity given out here.
T>x....................1
y<m or m>y ......2
same sided inequality can be added . hence, T+m> x+y
T>x....................1
y<m or m>y ......2
same sided inequality can be added . hence, T+m> x+y
