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Line M is perpendicular to line l
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19 May 2017, 02:08
19 May 2017, 02:08
Expert Reply
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Question Stats:
76% (00:54) correct
23% (00:49) wrong based on 156 sessions
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Line l passes through \((- \sqrt{2}, \sqrt{3} )\) and \(( \sqrt{2}, -\sqrt{3} )\). Line M is perpendicular to line L
Quantity A |
Quantity B |
The slope of L |
The slope of M |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Line L passes
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09 Oct 2017, 08:22
09 Oct 2017, 08:22
2
Given that line m is perpendicular to line l and the slope of a perpendicular line is the opposite reciprocal of the other.
Than it is enough to notice that line l slope is some negative stuff divided by some positive stuff, thus it is negative. Line m slope is then positive.
Quantity B is greater and B is the answer!
Than it is enough to notice that line l slope is some negative stuff divided by some positive stuff, thus it is negative. Line m slope is then positive.
Quantity B is greater and B is the answer!
Re: Line L passes
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09 Oct 2017, 11:13
09 Oct 2017, 11:13
3
Carcass wrote:
Line l passes through \((- \sqrt{2}, \sqrt{3} )\) and \(( \sqrt{2}, -\sqrt{3} )\). Line M is perpendicular to line l
Quantity A |
Quantity B |
The slope of l |
The slope of M |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Detailed explanation
Now we know slope of line\(m = \frac{(y2 - y1 )}{(x2 -x1)}\)
Therefore the slope of line\(l= \frac{(y2 - y1 )}{(x2 -x1)}\) [ where y2 = \(-\sqrt{3}\), y1 =\(\sqrt{3}\)and x2 = \(\sqrt{2}\) and x1 =\(-\sqrt{2}\) ]
\(=(-\sqrt{3}-\sqrt{3})/(\sqrt{2}+\sqrt{2})\)
\(= -\sqrt{3}/\sqrt{2}\)
Now slope of line \(M = \sqrt{2}/\sqrt{3}\) (Since the slope M is perpendicular to line l and we know the slope is negative reciprocal)
Hence option B is greater since it is positive value
