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Re: Given two intersecting circles.. [#permalink]
The answer is 20. The distance between intersection points is more than a circle's radius, hence one of the circle is pretty smaller than the other.
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Re: Given two intersecting circles.. [#permalink]
One circle has to be larger than the other one for the distance to be greater than one of the radii
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Re: Given two intersecting circles.. [#permalink]
Sandy, how are we supposed to approximate square roots?
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Re: Given two intersecting circles.. [#permalink]
sandy wrote:
In this case let the circles intersect at B and F respectively, as shown in figure below:

Attachment:
Inkedintersecting.gif


Now line AC is a perpedicular bisector of BF at point D and AB=15 and BC=25. Hence to find the distance we need to calculate AD and DC.

Now triangle ABD is right triangle AD=\(\sqrt{AB^2-BD^2}=\sqrt{15^2-10^2}=11.18\)

Now triangle CBD is right triangle CD=\(\sqrt{BC^2-BD^2}=\sqrt{25^2-10^2}=22.91\).

Hence total distance AC = 11.18+22.91=34.09.


The portion marked in red are properties of a circle.


I can't tell where you got the 10 from, it shouldn't be as simple as just subtracting 25 from 15 that doesn't make sense.
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Re: Given two intersecting circles.. [#permalink]
QuantumWonder wrote:
sandy wrote:
In this case let the circles intersect at B and F respectively, as shown in figure below:

Attachment:
Inkedintersecting.gif


Now line AC is a perpedicular bisector of BF at point D and AB=15 and BC=25. Hence to find the distance we need to calculate AD and DC.

Now triangle ABD is right triangle AD=\(\sqrt{AB^2-BD^2}=\sqrt{15^2-10^2}=11.18\)

Now triangle CBD is right triangle CD=\(\sqrt{BC^2-BD^2}=\sqrt{25^2-10^2}=22.91\).

Hence total distance AC = 11.18+22.91=34.09.


The portion marked in red are properties of a circle.


I can't tell where you got the 10 from, it shouldn't be as simple as just subtracting 25 from 15 that doesn't make sense.

It is in the question,
Given two intersecting circles, one with radius 15 and another with radius 25. If the distance between the two intersecting points is 20, then find the distance between the centers of the two circles?

Then perpendicular bisector properties of a circle.
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Given two intersecting circles.. [#permalink]
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Incognito wrote:
Sandy, how are we supposed to approximate square roots?


You are not required to, you will have an onscreen calculator in the exam!

Howeover, you can remember these 5 values in particular, that will help you:
\(\sqrt{2} = 1.41, \sqrt{3} = 1.73, \sqrt{5} = 2.23, \sqrt{7} = 2.64, \sqrt{10} = 3.16\)
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Re: Given two intersecting circles.. [#permalink]
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Re: Given two intersecting circles.. [#permalink]
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