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In the figure, the area of rectangle ABCD is 100. What is th
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01 Oct 2018, 13:46
01 Oct 2018, 13:46
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#GREpracticequestin In the figure, the area of rectangle ABCD is 100.jpg [ 15 KiB | Viewed 8937 times ]
In the figure, the area of rectangle ABCD is 100. What is the area of the square EFGH ?
(A) 256
(B) 275
(C) 309
(D) 399
(E) 401
Re: In the figure, the area of rectangle ABCD is 100. What is th
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13 Jan 2019, 08:55
13 Jan 2019, 08:55
1
Area of rectangle ABCD = 100
(x+3) (x+2) = 100
Multiplying polynomials using FOIL (First, Outer, Inner, Last), we get,
x(x + 5) = 94
Area of square EFGH = (2X + 5) ^ 2 ( since side of a square = (2x+5) )
Multiplying polynomials (2x + 5 ) ^ 2 using FOIL method, we get,
4x (x +5) + 25 = 4 * 94 +25 = 401.
Thus, answer is E.
(x+3) (x+2) = 100
Multiplying polynomials using FOIL (First, Outer, Inner, Last), we get,
x(x + 5) = 94
Area of square EFGH = (2X + 5) ^ 2 ( since side of a square = (2x+5) )
Multiplying polynomials (2x + 5 ) ^ 2 using FOIL method, we get,
4x (x +5) + 25 = 4 * 94 +25 = 401.
Thus, answer is E.
Re: In the figure, the area of rectangle ABCD is 100. What is th
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13 Jan 2019, 19:53
13 Jan 2019, 19:53
Expert Reply
Carcass wrote:
Attachment:
recs.jpg
In the figure, the area of rectangle ABCD is 100. What is the area of the square EFGH ?
(A) 256
(B) 275
(C) 309
(D) 399
(E) 401
So we have (x+3)(x+2)=100...\(x^2+5x+6=100...x^2+5x=94\)
We are looking for (2x+5)(2x+5)=\(4x^2+20x+25=4(x^2+5x)+25=4*94+25=401\)
E
