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In the figure, ABCD is a rectangle, and the area of ∆ACE is
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01 Oct 2018, 13:32
01 Oct 2018, 13:32
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Question Stats:
92% (00:58) correct
7% (02:36) wrong based on 27 sessions
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#GREpracticequestion In the figure, ABCD is a rectangle, and the area.jpg [ 18.09 KiB | Viewed 4739 times ]
In the figure, ABCD is a rectangle, and the area of ∆ACE is 10. What is the area of the rectangle?
(A) 18
(B) 22.5
(C) 36
(D) 44
(E) 45
Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is
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02 Oct 2018, 06:36
02 Oct 2018, 06:36
solution pls??
Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is
[#permalink]
02 Oct 2018, 10:42
02 Oct 2018, 10:42
1
Hi,
Area of traingle ACE is 10. Calculate the 'height' of the traingle to get the width of the rectangle. Length of the rectangle is given as 5+4=9.
Height of triangle
1/2*5*h =10
h =10*2/5=4
Area of rectangle = 9*4=36
Area of traingle ACE is 10. Calculate the 'height' of the traingle to get the width of the rectangle. Length of the rectangle is given as 5+4=9.
Height of triangle
1/2*5*h =10
h =10*2/5=4
Area of rectangle = 9*4=36
