GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure above, the circle is inscribed in the square.
[#permalink]
06 Oct 2018, 15:59
06 Oct 2018, 15:59
1
Expert Reply
00:00
Question Stats:
94% (00:32) correct
5% (01:04) wrong based on 76 sessions
Hide Show timer Statistics
Attachment:
Capture.JPG [ 12.19 KiB | Viewed 3633 times ]
In the figure above, the circle is inscribed in the square.
The area of the circle is \(9\pi\).
Quantity A |
Quantity B |
The area of the square |
\(30\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In the figure above, the circle is inscribed in the square.
[#permalink]
12 Jan 2019, 06:27
12 Jan 2019, 06:27
πr^2=9
r=3 (since r is not negative)
2r=2*3=6
Area of square = 6^2 = 36
Answer A
r=3 (since r is not negative)
2r=2*3=6
Area of square = 6^2 = 36
Answer A
In the figure above, the circle is inscribed in the square.
[#permalink]
04 Jan 2024, 20:51
04 Jan 2024, 20:51
1
The area of the circle is \(9\pi\)
\(\pi r^2 = 9\pi\)
\(r^2 = 9\)
\(r = 3\)
Twice the radius is \(6\) and will give the diameter of the circle as well as the length of any side of the square.
Therefore the area of the square will be \(6 \times 6 = 36\)
Quantity A is greater than B
\(\pi r^2 = 9\pi\)
\(r^2 = 9\)
\(r = 3\)
Twice the radius is \(6\) and will give the diameter of the circle as well as the length of any side of the square.
Therefore the area of the square will be \(6 \times 6 = 36\)
Quantity A is greater than B
